Asked by LIA
Find the exact value of the slope of the line which is tangent to the curve given by the equation
r = 2 + cos θ at theta equals pi over 2 . You must show your work. (10 points) Please check if this is right. I put a lot of work into this please check!
x= 2 cos θ + cos^2 θ
y=2 sin θ + sin θ cos θ
dx/dθ = 2 sin θ (1+cos θ)
dy/dt = 2cos θ + cos 2θ
dy/dx = (dy/dt)/(dx/dt)
At π/2 x= 0, y= 2 and dy/dx = 1/2
The tangent is 1/2 = (y-2)/x
y = (x/2)+ 2
slope = 1/2
r = 2 + cos θ at theta equals pi over 2 . You must show your work. (10 points) Please check if this is right. I put a lot of work into this please check!
x= 2 cos θ + cos^2 θ
y=2 sin θ + sin θ cos θ
dx/dθ = 2 sin θ (1+cos θ)
dy/dt = 2cos θ + cos 2θ
dy/dx = (dy/dt)/(dx/dt)
At π/2 x= 0, y= 2 and dy/dx = 1/2
The tangent is 1/2 = (y-2)/x
y = (x/2)+ 2
slope = 1/2
Answers
Answered by
Coronado49
looks good!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.