Asked by Anonymous
Two parallel paths 26 m apart run east-west through the woods. Brooke jogs east on one path at 2 km/h, while Jamail walks west on the otherpath at 3
km/h. If they pass each other at time 𝑡=0, how far apart are they 5s later, and how fast is the distance between them changing at that moment?
The distance between them at 𝑡=5
is 𝐿
I converted from km/h to m/s 2km/h = 0.555m/s and 3km/h = 0.833 m/s and I'm not sure where to go from there.
km/h. If they pass each other at time 𝑡=0, how far apart are they 5s later, and how fast is the distance between them changing at that moment?
The distance between them at 𝑡=5
is 𝐿
I converted from km/h to m/s 2km/h = 0.555m/s and 3km/h = 0.833 m/s and I'm not sure where to go from there.
Answers
Answered by
oobleck
At time t, the distance z is
z^2 = (.555t+.833t)^2 + 26^2 = 1.927t^2 = 26^2
z dz/dt = 3.853t
now just find z(5) and solve for dz/dt
z^2 = (.555t+.833t)^2 + 26^2 = 1.927t^2 = 26^2
z dz/dt = 3.853t
now just find z(5) and solve for dz/dt
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