Question
If triangle DEF similar to triangle KLM such that DE=(2x+2)cm,DF=(5x-7)cm,KL=2cm,KM=3cm and EF=10cm,find the LM.
Answers
oobleck
DE/KL = DF/KM = EF/LM
(2x+2)/2 = (5x-7)/3
6x+6 = 10x-14
x = 5
10/LM = x+1 = 6
LM = 5/3
(2x+2)/2 = (5x-7)/3
6x+6 = 10x-14
x = 5
10/LM = x+1 = 6
LM = 5/3
ARsema
Thank you
mesud birhanu
LM=5/3
mesud birhanu
LM=5/3
Lidiya
LM 5/3c.m