Asked by updy ina xasan
If triangle DEF similar to triangle KLM such that DE=(2x+2)cm,DF=(5x-7)cm,KL=2cm,KM=3cm and EF=10cm,find the LM.
Answers
Answered by
oobleck
DE/KL = DF/KM = EF/LM
(2x+2)/2 = (5x-7)/3
6x+6 = 10x-14
x = 5
10/LM = x+1 = 6
LM = 5/3
(2x+2)/2 = (5x-7)/3
6x+6 = 10x-14
x = 5
10/LM = x+1 = 6
LM = 5/3
Answered by
ARsema
Thank you
Answered by
mesud birhanu
LM=5/3
Answered by
mesud birhanu
LM=5/3
Answered by
Lidiya
LM 5/3c.m
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