Asked by Alice
Find the velocity vector for a particle whose position vector is (2t, 5) for all t. (15 points)
A) (2, 0)
B) (t^2, 5t)
C) (t^3/3 , 5t^2/2)
D) square root of 4t^2 + 25
A) (2, 0)
B) (t^2, 5t)
C) (t^3/3 , 5t^2/2)
D) square root of 4t^2 + 25
Answers
Answered by
R_scott
d/dt 2t = 2
d/dt 5 = 0
d/dt 5 = 0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.