Asked by Lia
s = ∫[0,π] √((dx/dt)^2 + (dy/dt)^2) dt
OH, I think I messed up somewhere! I got 25.693, is this right? Please Help!
OH, I think I messed up somewhere! I got 25.693, is this right? Please Help!
Answers
Answered by
oobleck
You know, it would be better to attach follow-ups to the actual question, where all the information is available.
I asked you for the actual integral you used. What did you actually evaluate?
I asked you for the actual integral you used. What did you actually evaluate?
Answered by
Lia
Sorry, I will do that from now. s = ∫[0,π] √((dx/dt)^2 + (dy/dt)^2) dt I used my calculator and plugged in the equation and got 25.693, is this right? I can't really explain the steps to how I got this answer
Answered by
oobleck
I guess. Without actually seeing the values you used for dx/dt and dy/dt I have no way of knowing. If you relied on your calculator to determine those derivatives, then I certainly hope that was the right answer.
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