Asked by Manmeet

100-(5x(3+4)
Answered by Manmeet
64
Answered by Adam Williams
did you just answer your own question?
Answered by oobleck
yes, and he got it wrong, both syntactically and computationally.
Answered by Adam Williams
Is x a variable if not this is how the problem should look like this:
100 - [5 x (3 + 4)]
Answered by Adam Williams
oobleck can you please answer my question?
Answered by oobleck
If x is a variable, it should be written as
100 - [5x (3 + 4)]
100 - 5x(7)
100 - 35x
Answered by OIP
​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]​ 100-[5X(3+4)]100−[5×(3+4)]V​ 100-[5X(3+4)]100−[5×(3+4)]
Answered by E
the answer is 65
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