Question

a sample of lead at an temperature of 22.5 C absorbs 2.25 x 10^4 kJ of heat. The sample's temperature increases to 30.5 C. Calculate the mass in grams of lead on the sample. The specific heat constant of lead is 0.128 J/g-C

Answer 1

heat in = specific heat * mass * change in temp
2.25 * 10^4 * 10^3 (need joules not k joules) = 0.128 J/g-C * m (30.5 - 22.5)
2.25 * 10^7 / 1.024 = m
m = 2.2 * 10^7 grams = 2.2 * 10^4 kg