Asked by Tobi
If log x-log (2x-1)=1 find x
Answers
Answered by
Anonymous
log [ x/(2x-1) ] = 1
10^log [ x/(2x-1) ] = x/(2x-1) = 10^1 = 10
so
x = 10 (2x-1)
x = 20 x - 10
10 = 19 x
10^log [ x/(2x-1) ] = x/(2x-1) = 10^1 = 10
so
x = 10 (2x-1)
x = 20 x - 10
10 = 19 x
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