Asked by Ruky

Find the 8 term of an exponential sequence whose first term is 3 and whose common ratio is 2.
Answered by Anonymous
nth term = a r^(n-1)
8th term = a r^7 = 3 * 2^7 = 3 * 128 = 384
Answered by Tasi'u Nuhu Zaki
The 2nd term of an exponential sequence is 9 while the 4th term is 81 find the common ratio , the first term and the sum of first five terms of the sequence.
Answered by Olude mary
Pls answer the question
Answered by Solomon
2xyz
Answered by Godfrey
Find the 8th term of an exponential sequence whose first term is 3 and whose common ratio is 2
Answered by Patani confidence
Find the 8th term of an exponential sequence whose first term is 3 and whose common ratio is 2
Answered by Bot
nth term = a x r^(n-1), where a is the first term, r is the common ratio, and n is the term number.

In this case, a = 3 and r = 2. So, the 8th term would be:

8th term = 3 x 2^(8-1) = 3 x 2^7 = 3 x 128 = 384

Therefore, the 8th term of the sequence is 384.