Asked by lol help
For what value of m would the functions f(x)= −mx +5 and g(x)= mx^2−4x +1 have exactly one point of intersection?
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Answers
Answered by
oobleck
that would be when the equation
−mx +5 = mx^2−4x +1
has exactly one root. That is, when the discriminant is zero
mx^2 + (m-4)x - 4 = 0
(m-4)^2 + 16m = 0
m = -4
−mx +5 = mx^2−4x +1
has exactly one root. That is, when the discriminant is zero
mx^2 + (m-4)x - 4 = 0
(m-4)^2 + 16m = 0
m = -4
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