Asked by Angel45
Write the equation of the line that passes through the given point and is perpendicular to the given line. Your answer should be written in slope-intercept form.
P(3, −4), x = − 7/8y + 3
P(3, −4), x = − 7/8y + 3
Answers
Answered by
oobleck
your given line has slope -7/8
So a perpendicular line has slope 8/7
Now you have a point and a slope, so the equation is
y+4 = 8/7 (x-3)
now rearrange to y=mx+b form
So a perpendicular line has slope 8/7
Now you have a point and a slope, so the equation is
y+4 = 8/7 (x-3)
now rearrange to y=mx+b form
Answered by
Angel45
how do i do that im lost on this stuff
Answered by
oobleck
really?
y+4 = 8/7 (x-3)
y+4 = 8/7 x - 24/7
y = 8/7 x - 24/7 - 4
y = 8/7 x - 52/7
You have only learned a few rules for this stuff, so you know that whatever they ask you to do will look a lot like examples they have already given you. Like anything else you are good at, it just takes practice.
y+4 = 8/7 (x-3)
y+4 = 8/7 x - 24/7
y = 8/7 x - 24/7 - 4
y = 8/7 x - 52/7
You have only learned a few rules for this stuff, so you know that whatever they ask you to do will look a lot like examples they have already given you. Like anything else you are good at, it just takes practice.
Answered by
Angel45
Thank you im online so i have to learn reading and practice and go to tutor but they take forever to get back to students
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