Asked by anonymous person
                Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Explain.
Jesse Benjamin
100x^2−100 =(10x)^2−10^2 100x^2−100 =100(x^2−1)
=(10x−10)(10x+10) =100(x−1)(x+1)
=10(x−1)(10)(x+1)
=100(x−1)(x+1)
            
        Jesse Benjamin
100x^2−100 =(10x)^2−10^2 100x^2−100 =100(x^2−1)
=(10x−10)(10x+10) =100(x−1)(x+1)
=10(x−1)(10)(x+1)
=100(x−1)(x+1)
Answers
                    Answered by
             PsyDAG
            
    10(x−1)(10)(x+1) 
    
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