Asked by anonymous person
Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Explain.
Jesse Benjamin
100x^2−100 =(10x)^2−10^2 100x^2−100 =100(x^2−1)
=(10x−10)(10x+10) =100(x−1)(x+1)
=10(x−1)(10)(x+1)
=100(x−1)(x+1)
Jesse Benjamin
100x^2−100 =(10x)^2−10^2 100x^2−100 =100(x^2−1)
=(10x−10)(10x+10) =100(x−1)(x+1)
=10(x−1)(10)(x+1)
=100(x−1)(x+1)
Answers
Answered by
PsyDAG
10(x−1)(10)(x+1)
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