Question

Let g(t)=(0.7)^t. Estimate g′(7) to within one decimal place by using a small enough interval.
g′(7)≈
(If you can show work please do!! trying to understand the whole problem if possible! Thanks!)

Answer 1

so pick ∆x = 0.01
That means that a good approximation for f'(7) would be
(f(7.01)-f(7))/(7.01-7)
now just crank 'er out.

Answer 2

Thank you!!! Got it!