Asked by dennyelle
Determine the value(s) of m so that the quadratic equation mx2+6x = −m has no real roots. (i.e. no solution)
help please!!
help please!!
Answers
Answered by
oobleck
the standard form is mx^2 + 6x + m = 0
to have no real roots, the discriminant must be negative.
6^2 - 4m^2 < 0
to have no real roots, the discriminant must be negative.
6^2 - 4m^2 < 0
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