Question

The length of a square doubled and the width of the square increased by 5 to form a rectangle. If the area of the rectangle is 48 cm2. What is the side length of the original square?

Help with this please!!
oobleck
if the square has side s, then
(2s)(s+5) = 48
mathhelper
Old square ..... x by x
new square .... 2x by x+5
2x(x+5) = 48

expand, re-arrange, then solve this quadratic