We can disregard the forces exerted by the water, as they will be negligible. To find the final speed of the two fish after the collision, we'll apply the conservation of momentum principle. The total momentum before the collision (momentum_1) will be equal to the total momentum after the collision (momentum_2).
momentum_1 = momentum_2
In this case, momentum is the mass of the fish multiplied by its velocity. The velocity of the fish is given in m/s:
momentum_1 = 18 kg * 3.2 m/s - 2 kg * 7.4 m/s
momentum_1 = 57.6 kg*m/s - 14.8 kg*m/s
momentum_1 = 42.8 kg*m/s
When the fish collide, they will move together at a new velocity (V), and their combined mass will be 20 kg since the smaller fish has a mass of 2 kg and the larger fish has a mass of 18 kg.
momentum_2 = (18 kg + 2 kg) * V
momentum_2 = 20 kg * V
Now we can equate momentums and solve for the new velocity (V):
42.8 kg*m/s = 20 kg * V
V = 42.8 kg*m/s / 20 kg
V = 2.14 m/s
After the collision, the fish will move together with a velocity of 2.14 m/s to the right.
A 18kg fish moving horizontally to the right at 3.2m/s swallows a 2kg fish that is swimming to the left at 7.4m/s. What is the speed of the forces exerted on the pitches by the water is neiligible
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