Asked by william

hello! I seem to be having some problem with the start of my grade 12 physics course in which my grade 11 course was cut short due to the pandemic so I just need a bit of an explanation of what I need to do

the question being at what time will a police cruiser pass a speeding car with these variables that I've figured out

police cruiser
initial velocity = 0
final velocity = 40
acceleration = 4 m/s

speeder
average velocity = 30m/s (they were moving at a constant speed with no acceleration)
acceleration = 0

sorry if I missed anything but I can include it if you need it
Answered by oobleck
they will meet when they have gone the same distance. Recall that the distance
s = vt + 1/2 at^2
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