Asked by Janet L McMillin
list the values for the four quantum numbers for each electron in fluorine
Answers
Answered by
DrBob222
I can do this but the point of this site is to help you do it. Tell me what you don't understand about it. Do you know the rules?
Answered by
DrBob222
Here are the rules.
n may have values of 1, 2, 3, 4, 5.............to infinity.
l (that's ell) may have values of 0, 1, 2, 3, 4, etc but may not be larger than n-1.
m<sub>l</sub> may have values of - l minimum to + l maximum with all integral numbers between; i.e., -l, -l+1, -l+2 etc to +l
m<sub>s</sub> may have values of +1/2 or -1/2 only.
So for the first two electron in the K shell,
n = 1, l = 0, m<sub>l</sub> = 0, and m<sub>s</sub> = +1/2
n = 1, l = 0, m<sub>l</sub> = 0, and m<sub>s</sub> = -1/2
Then for the third electron which is the first one in the L shell,
n = 2 so l may be 0 or 1, m<sub>l</sub>may be -1, 0, +1 and for each of those m<sub>s</sub>may be +1/2 or -1/2 etc.
Be explicit if you have questions.
n may have values of 1, 2, 3, 4, 5.............to infinity.
l (that's ell) may have values of 0, 1, 2, 3, 4, etc but may not be larger than n-1.
m<sub>l</sub> may have values of - l minimum to + l maximum with all integral numbers between; i.e., -l, -l+1, -l+2 etc to +l
m<sub>s</sub> may have values of +1/2 or -1/2 only.
So for the first two electron in the K shell,
n = 1, l = 0, m<sub>l</sub> = 0, and m<sub>s</sub> = +1/2
n = 1, l = 0, m<sub>l</sub> = 0, and m<sub>s</sub> = -1/2
Then for the third electron which is the first one in the L shell,
n = 2 so l may be 0 or 1, m<sub>l</sub>may be -1, 0, +1 and for each of those m<sub>s</sub>may be +1/2 or -1/2 etc.
Be explicit if you have questions.
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