Asked by tinkerbell
find n and r in a geometric series for which sn=93, an=48 and a1=3.
Answers
Answered by
oobleck
3r^(n-1) = 48
r^(n-1) = 16
2^4 = 16, so
r=2 and n=5
check:
S5 = 3(2^5-1) = 3*31 = 93
r^(n-1) = 16
2^4 = 16, so
r=2 and n=5
check:
S5 = 3(2^5-1) = 3*31 = 93
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