Asked by Anonymous
                Each of the 7 children, in turn throws a ball once at a target. Calculate the number of ways the children can be arranged in order to take the throws.
Given that 3 of the children are girls and 4 are boys, calculate the number of ways the children can be arranged in order that
a. successive throws are made by boys and girls alternately,
b. a girl taken the first throw and a boy takes the last throw.
            
        Given that 3 of the children are girls and 4 are boys, calculate the number of ways the children can be arranged in order that
a. successive throws are made by boys and girls alternately,
b. a girl taken the first throw and a boy takes the last throw.
Answers
                    Answered by
            Haseeb
            
    no. of ways the children can be arranged to take the throws: 
7p7 = 5040 ways.
for successive throws:
4p4 * 5p3 = 144 ways
for girl takes the first and boy the last:
3p1 * 5p5 *4p*1 = 1440 ways
    
7p7 = 5040 ways.
for successive throws:
4p4 * 5p3 = 144 ways
for girl takes the first and boy the last:
3p1 * 5p5 *4p*1 = 1440 ways
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