you want to decrease the concentration by a factor of 3/19
So you need to increase its volume by a factor of 19/3
1L = 19/3 * 3/19 L
so you want to to take 3/19 L of the 19M NaOH and add water to get 1000mL
That is, add 842 mL of H2O to 158 mL of the 19M NaOH
You are a work study student in our chemistry department. Amy, your supervisor has just asked you to prepare 1000ml of 3.00M NaOH solution for tomorrow's undergraduate experiment. The Stock Solutions cabinet is under the Stockroom Explorer. You will find find a 2.50 liter bottle containing 19M NaOH. Please prepare a flask containing 1000ml of a 3.00M solution. To ensure proper credit, please write your calculations in the space given below.
2 answers
With no exclusions listed I would take 157.9 mL of 19 M NaOH, add to a 1000 mL volumetric flask, then make to the mark with distilled water, stopper, mix thoroughly, label. Calculations:
mL1 x M1 = mL2 x M2
mL1 x 19M = 1000 mL x 3.00 M
mL1 = 1000 mL x 3.00 M/19 M = 157.9 mL
mL1 x M1 = mL2 x M2
mL1 x 19M = 1000 mL x 3.00 M
mL1 = 1000 mL x 3.00 M/19 M = 157.9 mL