At 950K for the reaction 2SO3 ⇌ 2 SO2 + O2, the initial pressure of SO3 is 32 atm. And the

Question

equilibrium pressure of O2 is 5.6 atm. Calculate Kp and Kc.

Answer 1

....................... 2SO3 ⇌ 2 SO2 + O2
I.......................32 atm........0..........0
C.......................-2x.............2x........x
E.....................32-2x............2x........x
The problem tells you that x = 5.6 atm so 2x must be 11.2 and 32-2x must be 32-11.2 = 20.8. Substitute these numbers into the Kp expression and solve.
Kp = p^2(SO2)*pO2/p*2(SO3).
For Kc, remember Kp =Kc*(RT)^delta n Post your work if you get stuck.