Asked by Taco
I have this question:
Consider the dichloropropane molecule, C3H6Cl2. Despite being a molecular compound, oxidation states can be assigned to the elements in butane.
+1Calculate the oxidation state of the carbon atoms. The oxidation state of the Cl atoms is at a value of -1 here. Show your work. Also fill in the oxidation state of the H atoms.
I have:
C3H6Cl2
Carbon 4x+6*1=0
4x+6=0
-6 -6
-1.5
4x = -6 , x=-6/4 /4 /4
x= -3/2 or -1.5
Oxidation state of c= -1.5
For H = 1+
Is this correct? Also what is strange about the oxidation state of carbon in dichloropropane?
Consider the dichloropropane molecule, C3H6Cl2. Despite being a molecular compound, oxidation states can be assigned to the elements in butane.
+1Calculate the oxidation state of the carbon atoms. The oxidation state of the Cl atoms is at a value of -1 here. Show your work. Also fill in the oxidation state of the H atoms.
I have:
C3H6Cl2
Carbon 4x+6*1=0
4x+6=0
-6 -6
-1.5
4x = -6 , x=-6/4 /4 /4
x= -3/2 or -1.5
Oxidation state of c= -1.5
For H = 1+
Is this correct? Also what is strange about the oxidation state of carbon in dichloropropane?
Answers
Answered by
DrBob222
C3H6Cl2
I would do it this way. Cl = 2*-1 = 2-
H = 6*+1 = 6+
3C + 6 + (-2) = 0
3C = -4
C = -4/3 each
C =
C = -4/3
I would do it this way. Cl = 2*-1 = 2-
H = 6*+1 = 6+
3C + 6 + (-2) = 0
3C = -4
C = -4/3 each
C =
C = -4/3
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