the height above ground level in meters of a missile launched vertically is given by :

h(t) = -16t^3 + 100t
at what time is the missile 72m above ground level? (t of time in a second)

1 answer

HEY typos???
Your equation uses g = 32 FEET /s^2 (so g/2 = 16 not 4.9) not 9.81 m/s^2
and uses t^3 instead of t^2
do physics much?
Do You want 72 feet maybe ?
if so
16 t^2 - 100 t + 72 = 0
solve quadratic
t on the way up = 0.83 second
t on the way down = 5.42 seconds