Asked by Nevaeh

Suppose a scrawny 20. kg Wyle was shot straight up with an initial velocity of +50 m/s.  
a.    Assuming that all his initial Ek was transformed into Eg, what is the maximum height he could reach?

b.    Suppose that 20% of his initial Ek were lost due to friction with the air (air resistance). 
What is the maximum height he could reach?
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Answered by oobleck
1/2 mv^2 = mgh
or, v^2 = 2gh
Answered by Nevaeh
Would that be 127.6 m and 102.08 m
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