Asked by Hiba
                1_  Al in 1.200 g impure [NH4Al (SO4) 2] (237 g / mol) is precipitated with NH3 as Al2O3 × H2O. The precipitate is filtered Al2O3 (102 g / mol) 0.178 g% What is the amount of Al (27 g / mol)?
2_ 100 ml 0.25 M NH3, 50ml 0.2 M HCl
(Ka=1.75×10^-5) pH= ?
3_ 0.250 M CH3COOH , 0.125 M NaOH 50 ml (CH3COOH Ka= 1.75×10^-5) pH=?
4_ Of CO2 (44 g/mol) (wanted) in CaCO (100 g/mol) what is the gravimetric factor?
            
        2_ 100 ml 0.25 M NH3, 50ml 0.2 M HCl
(Ka=1.75×10^-5) pH= ?
3_ 0.250 M CH3COOH , 0.125 M NaOH 50 ml (CH3COOH Ka= 1.75×10^-5) pH=?
4_ Of CO2 (44 g/mol) (wanted) in CaCO (100 g/mol) what is the gravimetric factor?
Answers
                    Answered by
            uglyfrogturd101
            
    sorry dude i'm not good at math
    
                    Answered by
            DrBob222
            
    4_ Of CO2 (44 g/mol) (wanted) in CaCO (100 g/mol) what is the gravimetric factor? 
<b>Interesting. I thought they stopped teaching gravimetric factors years ago. Also I thought that was a mistake. I assume you meant CaCO3 and not CaCO.
The factor is (molar mass CO2/molar mass CaCO3) = 44/100 = ?</b>
3_ 0.250 M CH3COOH , 0.125 M NaOH 50 ml (CH3COOH Ka= 1.75×10^-5) pH=?
<b> mols CH3COOH = 0.250
CH3COOH + NaOH --> CH3COONa + H2O
How much CH3COOH? Gotta know that.
#2. You have the Ka for NH3 wrong.
#1. I can't make sense of the problem the way you've presented it.
    
<b>Interesting. I thought they stopped teaching gravimetric factors years ago. Also I thought that was a mistake. I assume you meant CaCO3 and not CaCO.
The factor is (molar mass CO2/molar mass CaCO3) = 44/100 = ?</b>
3_ 0.250 M CH3COOH , 0.125 M NaOH 50 ml (CH3COOH Ka= 1.75×10^-5) pH=?
<b> mols CH3COOH = 0.250
CH3COOH + NaOH --> CH3COONa + H2O
How much CH3COOH? Gotta know that.
#2. You have the Ka for NH3 wrong.
#1. I can't make sense of the problem the way you've presented it.
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