Asked by Peter Godson
For an arithmetical sequence, the first term is 2 and the common difference is 3. Find the sum of the 11 terms of the sequence.
Answers
Answered by
kumar
f1=2, d=3
sum=n/2[2a+(n-1)d]
=11/2[2x2+(11-1)3]
=11/2[4+10x3]
= 11/2[34] = 11x17 =187
sum=n/2[2a+(n-1)d]
=11/2[2x2+(11-1)3]
=11/2[4+10x3]
= 11/2[34] = 11x17 =187
Answered by
Christopher sharon nneka
I dont really understand
Answered by
Christopher sharon nneka
Thanks but f represent what
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