Please provide the steps.

Question

The acid dissociation constant for a weak acid is determined to by 5.883 x 10-4 (± 0.02%). What is the pKa of the acid?

Answer 1

pKa = -log Ka = -log (5.883E-4 +/- 0.0002
s = +/- 0.434 x (0.0002E-4/5.883E-4) = +/- 0.01475, then
pKa = -log(5.883E-4) +/- 0.01475
pKa = +3.230 +/- 0.01475

In line 2 I would round that to 0.0148 and use that in line 4

Answer 2

Thank you!