Asked by Anonymous
How many term has theA.P whose first term is 15 and the term is 56 given that the common difference is 3
Answers
Answered by
Anonymous
a =15
d = 3
term n = a + (n-1) d
56 = 15 + (n-1)3
41 = 3 n - 3
3 n = 44
no way
typo ?
d = 3
term n = a + (n-1) d
56 = 15 + (n-1)3
41 = 3 n - 3
3 n = 44
no way
typo ?
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