The point (-1,-5) is equidistant from the lines 3x-4y-2=0 and 3x-4y+k=0, where k≠-2. Find k

Answer 1

|3(-1)-4(-5)-2| = |(3(-1)-4(-5)+k|
|15| = |17+k|
17+k = ±15
k = ±15-17
k = -2 or -34