Asked by Anonymous
solve the following equation: 5^x+2-2(5^x-1)=3075
Answers
Answered by
Anonymous
5^x+2-2(5^x-1)=3075
5^x + 2 - 2* 5^x + 2 = 3075
-5^x = 3071
5^x = -3071
x log 5 = log -3071
well 10^log -3071 = -3071
hmmmm
5^x + 2 - 2* 5^x + 2 = 3075
-5^x = 3071
5^x = -3071
x log 5 = log -3071
well 10^log -3071 = -3071
hmmmm
Answered by
oobleck
assuming the usual carelessness with parentheses, let's go with
5^(x+2)-2(5^(x-1))=3075
5^x * 5^2 - 2(5^x / 5^1) = 3075
25*5^x - 2/5 * 5^x = 3075
123*5^x = 15375
5^x = 125
x = 3
5^(x+2)-2(5^(x-1))=3075
5^x * 5^2 - 2(5^x / 5^1) = 3075
25*5^x - 2/5 * 5^x = 3075
123*5^x = 15375
5^x = 125
x = 3
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