(2a-1)^2 = (2a-1)(2a-1)
1 - 4a^2 = -(2a-1)(2a+1)
8a^3 - 12a^2 + 6a - 1 = (2a-1)(2a-1)^2
so, what do you think?
Find the least common multiple of
(2a −1)^2, 1−4a^2, and 8a^3 −12a^2 +6a −1
2 answers
emwqkleqwe
(2a −1)^2, 1−4a^2, and 8a^3 −12a^2 +6a −1
2 answers
2 answers
0 answers
4 answers
1 answer