Asked by BLM
The angle p, to the nearest degree, in a triangle with side lengths p=15cm, q=19cm and r=22cm, is?
I missed a class to get corona tested and my teacher says its my fault that I don't know how to do this. My friend tried to explain it to me but Im not sure he understands it either. Help!
I missed a class to get corona tested and my teacher says its my fault that I don't know how to do this. My friend tried to explain it to me but Im not sure he understands it either. Help!
Answers
Answered by
oobleck
If p,q,r are sides, then p is not an angle. Maybe you meant P.
So use the law of cosines.
p^2 = q^2 + r^2 - 2qr cosP
15^2 = 19^2 + 22^2 - 2*19*22 cosP
cosP = 155/209
P = 42.13°
So use the law of cosines.
p^2 = q^2 + r^2 - 2qr cosP
15^2 = 19^2 + 22^2 - 2*19*22 cosP
cosP = 155/209
P = 42.13°
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