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Given the following reaction that has an enthalpy of +128 kJ.

CH3OH(l) ---> CO(g) + 2H2(g)

How many kJ of heat are consumed when 50.1 g of CH3OH(l) reacts as shown in the equation?

1 answer

So your reaction tells you that 128 kJ is consumed when 1 mol (32 g CH3OH) is used. You want to know for 50.1 so that is
128 kJ x (50.1/32) = ? kJ
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