Asked by carter

solve the system x^2+2x+2y=5 and 3x^2-4x=3+y
Answered by oobleck
you have y = 3x^2 - 4x -3 so just solve
x^2 + 2x + 2(3x^2 - 4x - 3) = 5
7x^2 - 6x - 11 = 0
now finish it off
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