Asked by adeola

what weight of silver is deposited of silver nitrate at the same time as 2.40g of copper(ll) sulphate solution when the two solution are arrange in series connected to a battery
Answered by adeola
pls help me out
Answered by DrBob222
Cu^2+(aq) + 2e --> Cu(s)
Ag^+(aq) + e ==> Ag(s)
First you must determine the coulombs needed to deposit 2.40 g Cu from CuSO4 solution.
63.54/2 = 31.77g Cu(s) can be deposited by 96,485 coulomb of electricity. So how many coulombs will be needed to deposit 2.40 g? That will be
96,485 x (2.40/31.77) = estimated 7,289 coulombs.

107.9 g/1 = 107.9 g Ag(s) will be deposited with 96,485 coulombs so how much Ag will be deposited with 7289 coulombs? That is
107.9 g Cu x (7,289/96,485) = ?
Check those numbers. Post your work if you get stuck.
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