The vertices of a quadrilateral ABCD are A (0, 5), B(9, 2), C (7, –4), and D(–2, –1). Is ABCD a rectangle? Prove using mathematical evidence and then justify your answer.

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Practice test question please help
ok hold on
dude im rlly sry but i cant help u with this
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anyone else, please?
the length of AB is √((9-0)^2 + (2-5)^2) = √81+9) = √90
The slope of AB is (2-5)/(9-0) = -1/3
Now check the other sides, and make sure that CD=AB and BC=AD
CD also has slope -1/3
BC and AD have slope 3
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