Asked by Nevaeh
a student connects an object with mass m to a rope with a length r and then rotates the rope around her head parallel to the ground. the object takes 0.5 seconds to complete one rotation.
mass= 50 kg. length of the rope = 1.2 m
what is the objects speed of rotation?
what is the objects centripetal acceleration?
Just want to check my answers
I'm pretty sure the first question answer is 15.08 m/s and the second answer is 189.51 m/s^2
Correct me if I'm wrong.
mass= 50 kg. length of the rope = 1.2 m
what is the objects speed of rotation?
what is the objects centripetal acceleration?
Just want to check my answers
I'm pretty sure the first question answer is 15.08 m/s and the second answer is 189.51 m/s^2
Correct me if I'm wrong.
Answers
Answered by
R_scott
s = 2 π r / t = 2 * π * 1.2 / .5 = 15.08
a = s^2 / r = 15.08^2 / 1.2 = 189.51
there are issues with significant figures
... the 5 figure result for c.a. when the best data number has 2 figures
... same case for speed
a = s^2 / r = 15.08^2 / 1.2 = 189.51
there are issues with significant figures
... the 5 figure result for c.a. when the best data number has 2 figures
... same case for speed
Answered by
Nevaeh
So would that make the tension required 9.47 N by any chance. That's what I got for the tension.
Answered by
R_scott
the tension supplies the force for the centripetal acceleration
f = m a = 50 * 189.51 = ?
you seem to be off by a factor of 100
the mass does not seem realistic for a person to swing around
f = m a = 50 * 189.51 = ?
you seem to be off by a factor of 100
the mass does not seem realistic for a person to swing around
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