Asked by some one
If the graph of y=f(x),xER is the same as y= |f(x)|,xER then...
A. f(x) may be of the form ax + b ,a (cant equal) 0 or of the form ax^2+bx+c, a (cant equal) 0
B. f(x) may be of the form ax + b,a c (cant equal) 0 but cannot be of the form ax^2+bx+c, a (cant equal) 0
C. f(x) may be of the form ax^2+bx+c, a (cant equal) 0 , but cannot be of the form ax + b,a c (cant equal) 0
D. f(x) cannot be of the form ax^2+bx+c, a (cant equal) 0 or ax + b,a c (cant equal) 0
*I put cant equal in place of the equal signs that have slashes on them
A. f(x) may be of the form ax + b ,a (cant equal) 0 or of the form ax^2+bx+c, a (cant equal) 0
B. f(x) may be of the form ax + b,a c (cant equal) 0 but cannot be of the form ax^2+bx+c, a (cant equal) 0
C. f(x) may be of the form ax^2+bx+c, a (cant equal) 0 , but cannot be of the form ax + b,a c (cant equal) 0
D. f(x) cannot be of the form ax^2+bx+c, a (cant equal) 0 or ax + b,a c (cant equal) 0
*I put cant equal in place of the equal signs that have slashes on them
Answers
Answered by
oobleck
recall the definition of |x|
|x| = x if x >= 0
|x| = -x if x < 0
so, you know that f(x) is never negative
a sloping straight line cannot satisfy that condition, but a quadratic (such as f(x) = x^2) can.
|x| = x if x >= 0
|x| = -x if x < 0
so, you know that f(x) is never negative
a sloping straight line cannot satisfy that condition, but a quadratic (such as f(x) = x^2) can.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.