Asked by Anonymous
                Struggling with this problem:
A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. The scale reads 848 N. As the elevator starts to move up, the scale reading increases to 968 N, then changes back to 848 N. What was the acceleration of the elevator?
            
            
        A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. The scale reads 848 N. As the elevator starts to move up, the scale reading increases to 968 N, then changes back to 848 N. What was the acceleration of the elevator?
Answers
                    Answered by
            oobleck
            
    add acceleration a to the g of gravity.
mg = 9.81m = 848, so m = 86.44 kg
86.44(g+a) = 968
a = 968/86.44 - 9.81 = 1.388 m/s^2
or, m(g+a)/mg = 968/848
a = 1.388
    
mg = 9.81m = 848, so m = 86.44 kg
86.44(g+a) = 968
a = 968/86.44 - 9.81 = 1.388 m/s^2
or, m(g+a)/mg = 968/848
a = 1.388
                    Answered by
            Anonymous
            
    848 = m g
so m = 848/g
968 = m g + m a
m a = 968 - m g = 968 - 848 = 120
a = 120/m = (120 / 848 ) g
now just put in whatever g is on your planet
    
so m = 848/g
968 = m g + m a
m a = 968 - m g = 968 - 848 = 120
a = 120/m = (120 / 848 ) g
now just put in whatever g is on your planet
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