GUYS PLEASE HELP!!!! URGENT!!!! 20 POINTS!! PLEASE I AM DESPERAT!!

find the product of the monomial and the polynomial:

1. xyz*(2x+3y^2-3z^2)

2. 4x^3y^3*(3x^3-7xy^2+2xy-y)

3. -4m n^3*(-3m^2n+12m n^2-6m+7n^2

User Icon for John John answered
3 years ago

all you do is multiply the coefficients (the numbers out in front) and when multiplying exponents you keep the base and add the exponents.)

You are using distributive law to multiply the monomial times each part of the binomial
3. -4m n^3*(-3m^2n+12m n^2-6m+7n^2
The first part of the answer is 12m^3 n^4
if there is no exponent like on m assume it is 1.

User Icon for John John answered
3 years ago

I should have said polynomial instead of binomial.

User Icon for rsm student rsm student answered
3 years ago

thx so much, but whats the answer?

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the product of a monomial and a polynomial, you need to use the distributive property. This property states that you need to multiply each term in the polynomial by the monomial. Let's go through each question step by step:

1. xyz * (2x + 3y^2 - 3z^2)
To find the product, multiply the monomial xyz by each term in the parentheses:
xyz * 2x = 2xyz^2
xyz * 3y^2 = 3xyz^2y^2
xyz * -3z^2 = -3xyz^3

So the product of xyz and (2x + 3y^2 - 3z^2) is 2xyz^2 + 3xyz^2y^2 - 3xyz^3.

2. 4x^3y^3 * (3x^3 - 7xy^2 + 2xy - y)
Again, use the distributive property to multiply each term in the parentheses by the monomial:
4x^3y^3 * 3x^3 = 12x^6y^3
4x^3y^3 * -7xy^2 = -28x^4y^5
4x^3y^3 * 2xy = 8x^4y^4
4x^3y^3 * -y = -4x^3y^4

The product of 4x^3y^3 and (3x^3 - 7xy^2 + 2xy - y) is 12x^6y^3 - 28x^4y^5 + 8x^4y^4 - 4x^3y^4.

Note that in both examples, you need to apply the commutative property to ensure that the terms in the final expression are in the correct order.