Asked by M
Write each expression as a sum or difference of logarithms. Express powers as factors.
log2(x^3/x - 3)
x > 3
Answer: 3 log2x - log2 (x-3)
Could someone show me the steps to get to this answer?
log2(x^3/x - 3)
x > 3
Answer: 3 log2x - log2 (x-3)
Could someone show me the steps to get to this answer?
Answers
Answered by
oobleck
Review the basic rules of logarithms.
log(a/b) = loga - logb
log(x^n) = n * log(x)
log(a/b) = loga - logb
log(x^n) = n * log(x)
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