Asked by lori
A piece of lead having a mass of 200.0 g and a temperature of 100.0 ˚C is placed in a cup of water initially at 22 ˚C. After stirring the final temperature of the water and lead is 25 ˚C. Calculate the heat energy that was lost by the lead to the water. Calculate the amount of water in the cup. C Pb = 0.160 J/g C
Answers
Answered by
DrBob222
heat lost by Pb.
q = mass Pb x specific heat Pb x (Tfinal-Tinital) = ?
part 2.
mass Pb x specific heat Pb x (Tfinal-Tinital) + mass H2O x specific heat H2O x (Tfinal - Tinitial)
Substitute into that equation and solve for mass H2O
Post your work if you get stuck.
q = mass Pb x specific heat Pb x (Tfinal-Tinital) = ?
part 2.
mass Pb x specific heat Pb x (Tfinal-Tinital) + mass H2O x specific heat H2O x (Tfinal - Tinitial)
Substitute into that equation and solve for mass H2O
Post your work if you get stuck.
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