f(x) = abs(sin(x)), -pi less than or equal to x less than or equal to pi

g(x) = x^2

let H(x) = g(f(x))
i got that H(x) would equal sin^2(x).

THIS IS WHERE I AM STUCK!
find the domain of H. do i still need to account for "-pi less than or equal to x less than or equal to pi" or is it all real numbers?

1 answer

Since they put that restriction on the domain of f(x), the same restriction should apply to g(f(x)). Ignore my previous comment about the domain being all real numbers in this case.