In △ABC, DE¯¯¯¯¯¯¯¯ bisects BA¯¯¯¯¯¯¯¯ and BC¯¯¯¯¯¯¯¯ at D and E, respectively. If BA=5, BC=2, and AC=6, explain whether DE=6.(1 point)
The length of DE¯¯¯¯¯¯¯¯ is not 6 because DE¯¯¯¯¯¯¯¯ is the midsegment of BC¯¯¯¯¯¯¯¯. So DE=1.
The length of DE¯¯¯¯¯¯¯¯ is not 6 because DE¯¯¯¯¯¯¯¯ is the midsegment of AC¯¯¯¯¯¯¯¯. S, DE=3.
The length of DE¯¯¯¯¯¯¯¯ is 6 because AC¯¯¯¯¯¯¯¯ is the midsegment of DE¯¯¯¯¯¯¯¯.
The length of DE¯¯¯¯¯¯¯¯ is not 6 because DE¯¯¯¯¯¯¯¯ is the midsegment of BA¯¯¯¯¯¯¯¯. So DE=2.5.
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please help me
This just like the previous post. The smaller triangle is 1/2 the size of the larger.