Asked by Bansari patel
Four identical particles each have charge q and mass m. They are released from rest at the vertices
of a square of side L. How fast is each charge moving when their distance from the center of the
square doubles?
of a square of side L. How fast is each charge moving when their distance from the center of the
square doubles?
Answers
Answered by
Anonymous
Calculate the potential energy of a particle at original location
( in general at distance integral from infinity to d of k Q1Q2 dr /r^2
= k Q1Q2 /r )
Do it again for bigger distance.
(1/2) m v^2 = decrease in potential energy
( in general at distance integral from infinity to d of k Q1Q2 dr /r^2
= k Q1Q2 /r )
Do it again for bigger distance.
(1/2) m v^2 = decrease in potential energy
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