Question

1) a car travelling at 50km per second from rest cover a distance of 10km in 40 minu,caculate the acceleration of car.
2) a car accelerate uniformly from rest at 5 meter per second square.determine it speed after 10 second.
3) a body is dropped from a height above a ground for a velocity after 4 second take g as 9.8mls square 4) a bird fly at 10mls for 3 second,15mls for 3 second and 20mls for 14 second .caculate the average speed of the bird.
5) a bell is throne vertically upward an initial velocity of 40 mls find (a) its velocity after 3 second (b) the maximum height attend and the time taken to reach
6)a body accelerate uniform rest at 2mls square.calculate the magnitude of it velocity after travelling in 9 meter

Answer 1

Post your attempts.
accelerate for time = t
cruise at 50 m/s (surely not at 50 km/s unless car is in orbit, check your typing for typos. Maybe 50 km / hour which is about 30 miles/hour ?)
cruise at 50 for time T
t + T = 40 min = 2,400 seconds
steady speed = 50 whatevers/whatever = 0 + a t
distance during acceleration = d = .5 a t^2
total distance = 40 dowhistles = d + D where D is distance at steady speed
so D = 50 T
40 = .5 a ^2 + 50 T

Answer 2

2) v = 0 + a t = 500

Answer 3

forgot decimal point
50.0