Asked by Eric
Solve x+x/sqrt x^2-1 = 2sqrt2
Answers
Answered by
Eric
2(x^2)+xsqrt3x^2+1 = 4
Answered by
Eric
Oops
Answered by
Eric
That was my question 😓
Answered by
oobleck
2x^2+x√(3x^2+1) = 4
x√(3x^2+1) = 4 - 2x^2
x^2 (3x^2+1) = 16 - 16x^2 + 4x^4
x^4 - 17x^2 + 16 = 0
(x^2-16)(x^2-1) = 0
x = ±1, ±4
But only x = -4,1 satisfy the original equation
x√(3x^2+1) = 4 - 2x^2
x^2 (3x^2+1) = 16 - 16x^2 + 4x^4
x^4 - 17x^2 + 16 = 0
(x^2-16)(x^2-1) = 0
x = ±1, ±4
But only x = -4,1 satisfy the original equation
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