Asked by khushi

At a particular school with 200 male students, 58-play football, 40-play basketball, and 8 play both. What is
the probability that a randomly selected male student plays
a) At least one sport
b) Neither sport
c) Only basketball
Answered by oobleck
58+40-8 = 90
(a) 90/200
(b) 110/200
(c) (40-8)/200
Answered by Anonymous
40 - 8 = 32 only basketball
58 - 8 = 50 only football
32 + 50 + 8 = 90 some sport (answer A)
200 - 90 = 110 = no sport at all (B)
did only basketball up top
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