Asked by Ishaan
The sum of two numbers is 15. Four times the smaller number is 60 less than twice the larger number. What is the larger number?
Answers
Answered by
PsyDAG
4s = 2L - 60
s = (2L-60)/4
s + L = (2L-60)/4 + L = 15
Solve for L.
s = (2L-60)/4
s + L = (2L-60)/4 + L = 15
Solve for L.
Answered by
R_scott
s + L = 15 ... s = 15 - L
4 s + 60 = 2 L
substituting ... 60 - 4 L + 60 = 2 L
solve for L
4 s + 60 = 2 L
substituting ... 60 - 4 L + 60 = 2 L
solve for L
Answered by
Anonymous
x = larger
15 - x = smaller
Four times the smaller number is 60 less than twice the larger number.
4(15 – x) = 2x - 60
60 - x = 2x - 60
Solve for x
15 - x = smaller
Four times the smaller number is 60 less than twice the larger number.
4(15 – x) = 2x - 60
60 - x = 2x - 60
Solve for x
Answered by
R_scott
is "Anonymous" so named because the response is incorrect?