Asked by Ishaan
                The sum of two numbers is 15. Four times the smaller number is 60 less than twice the larger number. What is the larger number?
            
            
        Answers
                    Answered by
            PsyDAG
            
    4s = 2L - 60
s = (2L-60)/4
s + L = (2L-60)/4 + L = 15
Solve for L.
    
s = (2L-60)/4
s + L = (2L-60)/4 + L = 15
Solve for L.
                    Answered by
            R_scott
            
    s + L = 15 ... s = 15 - L
4 s + 60 = 2 L
substituting ... 60 - 4 L + 60 = 2 L
solve for L
    
4 s + 60 = 2 L
substituting ... 60 - 4 L + 60 = 2 L
solve for L
                    Answered by
            Anonymous 
            
    x = larger 
15 - x = smaller
Four times the smaller number is 60 less than twice the larger number.
4(15 – x) = 2x - 60
60 - x = 2x - 60
Solve for x
    
15 - x = smaller
Four times the smaller number is 60 less than twice the larger number.
4(15 – x) = 2x - 60
60 - x = 2x - 60
Solve for x
                    Answered by
            R_scott
            
    is "Anonymous" so named because the response is incorrect?
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.